Calculate the amount of heat power that is generated by the isothermal process

AI Thread Summary
In an isothermal process, the temperature remains constant, which implies that the internal energy of an ideal gas is also constant. According to the first law of thermodynamics, the change in heat energy is equal to the mechanical work done on the surroundings. For this scenario, since the internal energy does not change, the heat added to the system (Q) is equal to the negative of the work done (W), leading to the equation Q = -W. Given that 200W of power is required, this indicates that the heat power generated by the isothermal process is also 200W. Understanding these principles allows for the calculation of heat power in isothermal conditions.
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Homework Statement



200W of power is required for an isothermal process of a larger cyclic process.
Use the first law of thermodynamics to calculate the amount of heat power that is generated by the isothermal process.

Homework Equations



Change in heat energy = change in internal energy + mechanical work done on surroundings

The Attempt at a Solution



I'm a little lost as to how to begin! I know an isothermal process is one in which the temperature remains constant but is that needed here? Or will it simply be employed in the rest of the question after this?

Also I know that I can change the mechanical work into (pressure)(change in volume) but I feel this leads nowhere due to the lack of other information in the question!
 
Last edited:
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hello,

in an isothermal process, the internal energy is also constant (assuming this is an ideal gas), and so Q=-W.
 
Oh ok - I should be good from there with the rest of the question... Thanks a million!
 
cheers.
 

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