Calculate the displacement of 3 different directions and distances?

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To calculate the net displacement from the movements of 130m north, 50m east, and 40m south, first determine the final coordinates after each movement. Starting at (0,0), moving 130m north results in (0,130), then moving 50m east brings the position to (50,130), and finally moving 40m south results in (50,90). The net displacement can be calculated using the Pythagorean theorem, which involves finding the distance from the origin (0,0) to the final point (50,90). The final displacement is approximately 58.31m at an angle that can be calculated using trigonometric functions.
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Can someone please help me understand how to calculate the displacement of 3 different directions and distances?
 
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130m due north, 50m due east, and then 40m due south how can i figure out the net displacement?
 
think of it like on graph paper where the center of the paper is (0,0). if you go straight up 130m you are at (0,130) if you then go straight right 100m you are at (100,130) then if you go left 250m you are at (-150,130). after adding/subtracting all the different movements you find your ending point. Use Pythagorean theorem to find the distance.
 

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