Calculate the emf of Battery w/ External & Internal Resistance

AI Thread Summary
The discussion revolves around calculating the electromotive force (emf) of a battery with given external and internal resistances. The external resistance is 2.50 ohms, and the current is 4.0 A, while the internal resistance is 0.50 ohms. The user applies the equations V = IR and E = V + Ir to find the voltage across the external resistance as 10V and the emf as 12V. Responses confirm that the user's logic and calculations appear correct, assuming no unusual diagram details. The final emf of the battery is therefore 12V.
Jabababa
Messages
52
Reaction score
0

Homework Statement


What is the emf of the battery shown?

there is an external resistance of 2.50 ohm and 4.0 A...The battery has an internal resistance of 0.50ohm

Homework Equations



V=Ir
V= E +/- IR


The Attempt at a Solution



Since the current is going away the battery then i use the equation V= E - Ir
To find the V of the whole battery V= IR, V=(4)(2.5) = 10V
E= V + Ir
E= 10 + (4)(0.5) = 12 V

please check see if its right. If I am not clear i can upload a picture.
 
Physics news on Phys.org
Jabababa said:

Homework Statement


What is the emf of the battery shown?

there is an external resistance of 2.50 ohm and 4.0 A...The battery has an internal resistance of 0.50ohm

Homework Equations



V=Ir
V= E +/- IR


The Attempt at a Solution



Since the current is going away the battery then i use the equation V= E - Ir
To find the V of the whole battery V= IR, V=(4)(2.5) = 10V
E= V + Ir
E= 10 + (4)(0.5) = 12 V

please check see if its right. If I am not clear i can upload a picture.

Again your logic appears good - unless the diagram is quite unusual.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top