Calculate the energy of the proton

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To calculate the energy of a proton moving in a magnetic field, the equations F=ma and F=qvB are used, leading to the determination of the proton's velocity as approximately 1,022,833 m/s. The force acting on the proton is calculated to be 1.882 x 10^-13 N. The discussion highlights the need to convert this force into energy, which is related to the kinetic energy of the proton due to its motion. The kinetic energy can be found using the formula KE = 0.5mv^2. Ultimately, the conversation emphasizes the relationship between the proton's velocity and its kinetic energy.
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Homework Statement



A proton moves in a circular path perpendicular to a 1.15T magnetic field. The radius of its path is 9.3mm. Calculate the energy of the proton in eV.

Homework Equations



F=ma=mv^2/r, F=qvB

The Attempt at a Solution



F=ma=mv^2/r=qvB

mv/r=qB
v=qBr/m=1.6*10^-19*1.15*0.0093=1022833

F=qvB=1.6*10^-19*1022833*1.15=1.882*10^-13

I don't know how to convert F to the energy...
Well, first of all, am I correct so far?
 
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Well, you've calculated the velocity. If the proton has velocity its moving, so what type of energy does it have?
 

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