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## Homework Statement

Okay, so this was Part 1:

... which I solved as follows:Water flows with a speed v down a rectangular pipe of dimensions s and l as shown. What is the rate

at which water accumulates in the bucket? (figure 1.28)

[tex]\phi=\int_{Surface} v \cdot da[/tex]

[tex]=\int_{Surface} v*da\cos\theta[/tex]

[tex]=\int_{Surface} v*da[/tex]

[tex]=\int_s\int_l v*(dsdl)=v*s*l[/tex]

Now this is Part 2: Figure 1.29

We slice the end of the pipe off at some angle [itex]\theta[/itex]. This does not change [itex]\Phi[/itex]. Express your formula for [itex]\Phi[/itex] in terms of the dimensions

*s*and

*l'*and [itex]\theta[/itex].

So is the main idea of this to use only the

*normal component*of

**A**in the integral? (normal to

**v**, that is).

Casey