Calculate the kinetic energy of the proton

[megkirch]

Homework Statement

proton (mass = 1.67x10-27kg) is confined in a one dimensional potential well of infinite height and width of 2.847 x10-14m. Calculate the kinetic energy of the proton in the state with quantum number 1 in MeV

Homework Equations

KE = ((h^2)*(n^2))/(8*m*L^2) = ans / 1.6E-13 = ans in Mev

The Attempt at a Solution

((6.6E-34^2)*(1^2))/(8*1.67x10-27*2.847 x10-14^2)=1.7368E-14/1.6E-13=.10855
this answer is wrong, I am not sure why or what I am doing wrong. please help

 

[truesearch]

when I did your calculation I got 4 x 10^-14/1.6 x 10^-13 = 0.252
Check your calculation again

 

[megkirch]

I just checked my calculation again, I came up with 0.252 also. Thank you!