Calculate the kinetic energy of two alpha particles

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To calculate the kinetic energy of two alpha particles resulting from the capture of a proton by lithium-7, one must first balance the nuclear reaction equation. The mass of the lithium nucleus is given as 7.01601u, and the proton's energy can be neglected. By adding the rest masses of the reactants and products, the difference in mass will yield the energy released, which translates into the kinetic energy of the alpha particles. The solution assumes no gamma radiation is emitted during the reaction. This method effectively allows beginners to approach similar physics problems.
emmadun
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if lithium 7 3 captures proton, it is divided into two alpha particles. Calculate the kinetic energy of the alpha particles. the proton energy can be neglected and the mass of the nucleus of Li is 7,01601u.
I only know how to write the equation: 3Li7 + 1H1 → 2He4 + 2He4

Can anyone help me? How do i calculate the kinetic energy of the alpha particles??
p.s sorry I am a beginner in physics and I am trying really hard to solve these kind of problems.

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Simple solution: Add the rest masses of both sides of the equation. The difference is then energy. Assuming no gamma rays, the energy becomes kinetic energy of the two alpha particles.
 
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