Calculate the magnitude and direction of the electric field intensity

[Inquiring_Mike]

Quick Physics Help...

X and Z represent point charges of -2.4 x 10^-3 C and +3.3 x 10^-2 C respectively. Calculate the magnitude and direction of the electric field intensity at point Y, 5.00 cm from X and 8.50 cm from Z (they all live in a line).

Can sumone help me?

 

[himanshu121]

Apply the superposition principle i.e Electric field at point will be equal to electic field due to X + due to Z.

 

[Inquiring_Mike]

So does 4.974 x 10^10 look good?

 

[himanshu121]

you didn't tell about the location of point ,is it left of X or right of Z or in between which will decide mag+dir

 

[Inquiring_Mike]

X -----5.0------- Y----------8.5--------Z

 

[himanshu121]

direction will be towards YX and magnitude=9x10^9(2.4x10^-3/5x 10^-2+ 3.3 x 10^-2/ 8.5x10^-2
=3.92 x 10^9

 

[Inquiring_Mike]

Ah... It all makes sense now...
THanks for the help!