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Benzoate
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Homework Statement
What is the radius of the n=1 orbit in C^5+ ? What is the energy of the electron in that orbit? What is the wavelength of the radiation emitted by C^5+ in the lyman alpha transition
Homework Equations
1/lambda=R*(1/(n^2)-1/(m^2) ); a(0)=(h/(2*pi))/(m*k*e^2);a(0)=.0529e-9m =5.29e-7 mE=-k*Z^2*e^2/2/((r)); r= a(0)*n^2/Z
The Attempt at a Solution
to find the radius , I know r=a(0)*n^2/Z ; Z is the atomic number. The atomic number of C^+5 is 5. r=(5.29e-7 m)*(1)^2/(5)= 1.06e-7 m
to Find energy E=-k*Z^2*e^2/(2*r)= (9e9)((5)^2)((1.609e-19 J)^2)/(2*(1.06e-7m))=2.74e-20=.170 eV
Now I'm asked to find the wavelength in the lyman alpha transition. Since I'm in the lyman transition , should I say one the transition state n=1? Maybe I don't need to find the other transition state. I could used the fact that 1/lambda=(1/hc)*(E(f)-E(i)) . I know from earlier in the problem that E(i) = .170 eV. For a lyman series E(f)= 13.6 eV . E(f)-E(i)/(hc)=1/lambda => lambda= hc/(E(f)-E(i))