- #1
Clari
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A coil of self-inductance 0.7H is joined in parallel with a non-inductive resistance of 50 ohm. Calculate the total current, the current throught the wattless and power components when connected to a supply of 200V at a frequency of 50Hz.
Here is my steps:
Impedance Z= root [ 50^2 + (2pi*50*0.7)^2 ] = 225.5 ohm
Total current = 200/ Z = 0.9756A
Am I right? as for the other two questions, i really don't know how to solve them. Please help me with it. Thank you!
Clari
Here is my steps:
Impedance Z= root [ 50^2 + (2pi*50*0.7)^2 ] = 225.5 ohm
Total current = 200/ Z = 0.9756A
Am I right? as for the other two questions, i really don't know how to solve them. Please help me with it. Thank you!
Clari