Calculating Absorber Thickness for Radiation Intensity Reduction - x=0.693/(miu)

Thread starter asdf1
Start date Oct 10, 2005
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Physics

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The discussion focuses on calculating the thickness of an absorber needed to halve radiation intensity, represented by the formula x=0.693/(miu). The term "a factor of 2" indicates that the radiation energy is reduced to half its original value. Participants note the similarity of 0.693 to the natural logarithm of 2, suggesting a mathematical connection. Clarification is sought on whether "factor" equates to "multiple" in this context. Understanding these concepts is crucial for accurate calculations in radiation physics.

Oct 10, 2005

asdf1

for the following question:
show that the thickness x of an absorber required to reduce the intensity of radiation by a factor of 2 is given by x=0.693/(miu)

my problem:
what is meant by "a factor of 2"?

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Oct 10, 2005

Tide

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It means that the energy is reduced to one half its starting value. BTW - 0.693 looks suspiciously close to \ln 2. ;)

Oct 10, 2005

asdf1

thanks! :)
so usually, factor=mutiple?

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