Calculating acceleration and brake force

AI Thread Summary
To calculate the average force exerted by the brakes on a 600kg car that comes to rest from 45m/s in 12m, the acceleration must first be determined using the equation v^2 = u^2 + 2as. The correct rearrangement of the equation leads to a = (v^2 - u^2) / (2s). After substituting the values, the calculated acceleration is 168.75 m/s². This value can then be used to find the average force using the formula Force = mass x acceleration. The discussion highlights the importance of correctly transposing equations in physics calculations.
cyberhev
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Homework Statement

Hi all, the question for revision is; A car of mass 600kg traveling at 45m/s comes to rest in 12m when the brakes are applied. What is the average force exerted by the brakes?

Homework Equations

Force = mass x acceleration V^2=u^2 +2as

The Attempt at a Solution

I know I need to work out the acceleration but am having trouble correctly transposing that equation I think its this v^2-u^2 divided by s =2a, its what to do with the 2 to get a on its own, does it then become 1/2 s on the other side?
 
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cyberhev said:

Homework Statement

Hi all, the question for revision is; A car of mass 600kg traveling at 45m/s comes to rest in 12m when the brakes are applied. What is the average force exerted by the brakes?



Homework Equations

Force = mass x acceleration V^2=u^2 +2as



The Attempt at a Solution

I know I need to work out the acceleration but am having trouble correctly transposing that equation I think its this v^2-u^2 divided by s =2a, its what to do with the 2 to get a on its own, does it then become 1/2 s on the other side?

You're using the correct equation, but it looks like you need some help in "solving for a" to get the acceleration.

Let's write out what you correctly have so far:

<br /> \frac{v^2-u^2}{s}=2a<br />

Hopefully that helps you see better what to do ... if not, then post again.

p.s. I'm not quite sure if
1/2 s
means "(1/2)s" or 1/(2s).
 
That is what i have so far, I am just not sure where the 2 goes so you just get a on its own, I was wondering the 2 then moves to the side of s to become1/2s.
 
If I solve that equation with 2a. I did the following 45x45-0x0, divided by 12 = 168.75 x 2 =337.5. Is this the correct acceleration?
 
\frac{v^2-u^2}{s}=2a

\Rightarrow \frac{v^2-u^2}{2s}=a
 
Yes I have it, thank you, my transposition of equations knowledge is in there, but its 15 years or so since I used it! I often write the suvat list out, i find it very helpful.
 
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