- #1
timelesstrix0
- 5
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Member warned about posting without the homework template
So i have a challenging question given by my teacher:
Jimmy and Drake are at rest and on ice (therefore, we can ignore friction). Jimmy pushes
Drake for 0.50 seconds. Drake comes to rest 25 metres away from where they were at rest
10.0 seconds after the push.
Jimmy has a mass of 60 kg and Drake has a mass of 75 kg. How fast will Jimmy be going
after he has finished pushing Drake?!
i wana know how the "0.50 seconds" of push time will affect how i do the question...
Right now i can find Drake's acceleration and use that to find the force applied on Drake and use 3rd law and say that Jimmy will have the same amount of force... but idk if I am doing this right because i do not know how the 0.5 seconds of push time is involved in the question
for my velocity calculation (which will be used for the acceleration) will i have to use 0.5 seconds as the initial time value when doing
v = Δd/Δt
so it will be like: v = 25-0/10-0.5
Jimmy and Drake are at rest and on ice (therefore, we can ignore friction). Jimmy pushes
Drake for 0.50 seconds. Drake comes to rest 25 metres away from where they were at rest
10.0 seconds after the push.
Jimmy has a mass of 60 kg and Drake has a mass of 75 kg. How fast will Jimmy be going
after he has finished pushing Drake?!
i wana know how the "0.50 seconds" of push time will affect how i do the question...
Right now i can find Drake's acceleration and use that to find the force applied on Drake and use 3rd law and say that Jimmy will have the same amount of force... but idk if I am doing this right because i do not know how the 0.5 seconds of push time is involved in the question
for my velocity calculation (which will be used for the acceleration) will i have to use 0.5 seconds as the initial time value when doing
v = Δd/Δt
so it will be like: v = 25-0/10-0.5