Calculating Angular Displacement of Ball Bearing

AI Thread Summary
To calculate the angular displacement of a ball bearing with a radius of 0.00765 m that rolls 0.05 meters, the formula d = θr can be used, where d is the linear distance traveled and r is the radius. The angular displacement θ can be found by rearranging the formula to θ = d/r, resulting in an angular displacement of approximately 6.54 radians. For calculating angular speed, the relationship v = ωr is relevant, where v is linear speed and ω is angular speed. The discussion also touches on the need to understand rotational kinetic energy in the context of energy conservation between translational and rotational forms. Additional clarification on the equations and concepts is requested for better understanding.
alex_boothby
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hi,

how do i work out the angular displacement of ball bearing 0.00765 m in radius over 0.05 meters?

i need it to work out angular speed.


thank you
 
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Perhaps you need:

d = \theta r

v = \omega r

Where the angle is measured in radians.
 
im doing this piece of work about a ball bearing rolling down an invlined slope and translational kinetic energy + rotational kinetic energy should = potential enegry.

but I am not sure how to work out rotational kinetic energy. I am not sure of the equations you just gave me, sorry, a little more help maybe?

can i not just say that the angular displacement is 0.05 meters? as that is how much we moved the ball bearing back each time?

thank you, but could i please have a little more help?
 

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