Calculating Average Power of 130V RMS Generator Circuit

AI Thread Summary
The discussion revolves around calculating the average power consumed by a generator circuit with a 130V RMS voltage, a 3.65kΩ resistor, and a 3.00μF capacitor at a frequency of 47.5Hz. The average power formula used is Pavg = (Vrms/Z)VrmsCos(17), where Z is the impedance calculated from the resistor and capacitor values. A participant initially calculated an average power of 0.1111 W, while the correct answer is 4.23 W. The error was attributed to incorrect setup of the frequency in the calculations. The importance of providing intermediate results for clarity in problem-solving was emphasized.
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Homework Statement



A generator with an rms voltage of 130V is connected in series to a resistor 3.65k\Omega and a capacitor 3.00\muF.

Using the frequency found in part A (47.5Hz), find the average power consumed by this circuit.

\phi = 17degrees

Homework Equations



Latex isn't working for me so I'm sorry for the formatting

Pavg = (Vrms/Z)VrmsCos(17)

Z=((36502+(1/(2*pi*47.5Hz*3.00*10-6Farad))2)(1/2)

Pavg = (Vrms/Z)VrmsCos(17)

Pavg = .1111 W

The answer is 4.23 W

I'm just trying to figure out where I went wrong.
 
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It's hard to tell where you went wrong because you haven't supplied much in the way of intermediate results. For example, what value did you get for Z, the magnitude of the impedance?

When I compute (Vrms/Z)VrmsCos(17) I get the expected answer.
 
After punching it through again I got the correct answer; I went wrong in the way I set up Hz; punching in 47.5^-1, since Hz = S^-1; but that's redundant...
 

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