Calculating Capacitor Charge & Voltage: A Problem

AI Thread Summary
To solve the capacitor problem, the charge at t = 30 microseconds can be found by calculating the area under the current curve, resulting in 1.25 microcoulombs. The voltage at t = 50 microseconds is determined by integrating the current up to that time and dividing by the capacitance of 0.25 microfarads. The energy stored in the capacitor is calculated using the final voltage, as energy is proportional to the square of the voltage. This approach clarifies the relationship between charge, voltage, and energy in capacitors. Understanding these calculations helps in grasping capacitor behavior in electrical circuits.
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Homework Statement


The current shown below is applied to a 0.25uF capacitor. The initial voltage on the capacitor is zero.
(a) Find the charge on the capacitor at t = 30us.
(b) Find the voltage on the capacitor at t = 50us.
(c) How much energy is stored in the capacitor by this current?

http://img296.imageshack.us/img296/1800/currentgraphyk8.png

http://img513.imageshack.us/img513/302/problemdescriptionqw0.png

Thank you very much for any help you offer. This has had me bogged down for a couple hours now and I just want to understand how they got those answers in the back of the book.
 

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There is no need to "work backwards."

The total charge accumulated at time t is the integral of the current up to time t. So find the area underneath the curve up to t = 30 us in order to find q(30 us). You should get 1.25 uC.
 


Finding the voltage requires exactly the same procedure as I described above for the charge. (After all, the voltage is simply proporational to the charge accumulated). You can see that from the equation you've been given. You just have to compute the integral up until t = 50 us, and then divide the answer by C.
 


I interpret part c to be asking how much energy is stored in the process of charging up this capacitor using this current (i.e., at the end of it all, how much energy is stored)? Therefore, all you have to do is calculate the energy based on the capacitor's final voltage.
 


Thank you very much for your help. It all works out now.
 
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