Calculating Capacity of Steel Rack: Yield Stress Issues

AI Thread Summary
The discussion revolves around calculating the load capacity of steel racks that support heavy gearboxes and pulleys. The racks, made of layered steel pipes, can carry approximately 25 tons, but the user is confused about yield stress calculations, which yield kilopascal values instead of the expected megapascals. Concerns are raised about the appropriateness of assigning this calculation to someone without professional engineering certification. The thread was ultimately closed, advising the user to consult a professional engineer for proper guidance and design approval. Seeking professional assistance is emphasized as crucial for safety and compliance.
RJCanz
Messages
2
Reaction score
0
TL;DR Summary
Load capacity on Racks with steel pipes as load carrier
Hi guys. Recently I've been assigned to know / calculate the capacity of the racks in our section. Our racks has layered steel pipes that are carrying the loads. After actual testing it can carry a load around 25 tons after yielding or having a bend. So my next step was to calculate for its yield stress so I can calculated an allowable stress and an allowable load with a factor of safety right after. However, after calculating it's stress in which I used force over area (A = 3 sq.m.) I calculated a stress which only results to a kilopascal value while I have searched yield stresses of some materias are mostly in megapascals(MPa) is there wrong with my calculations? If there is, can you help me. Thank you!
 
Engineering news on Phys.org
Welcome to the PF. :smile:
RJCanz said:
Summary:: Load capacity on Racks with steel pipes as load carrier

Recently I've been assigned to know / calculate the capacity of the racks in our section. Our racks has layered steel pipes that are carrying the loads. After actual testing it can carry a load around 25 tons after yielding or having a bend.
That's a pretty heavy load! What is the application? If the racks fail, where does the load fall?

And why have you been assigned this calculation if you have to ask for help on the Internet? Seems strange to me...
 
berkeman said:
Welcome to the PF. :smile:

That's a pretty heavy load! What is the application? If the racks fail, where does the load fall?

And why have you been assigned this calculation if you have to ask for help on the Internet? Seems strange to me...
Apparently our boss doesn't know its capacity in tons so he assigned me to do it. Our section is overhauling of gearboxes, pulleys etc. And after these are fixed it is stacked in those racks. Our racks has 2-3 layers and the 25tons I have said was the capacity only of 1 layer. But I wondered when I computed for the stress with that known weight it is only in kilopascals so I wonder if it's wrong bc I have seen mostly stress capacities are is mega pascals
 
I'm guessing that you are not based in the US, because (hopefully) we would require professional engineer certification to be doing calculations like this. I will temporarily lock this thread to ask the other Mentors whether we should allow your thread to go forward...

UPDATE -- The thread will remain closed. Please seek the help of a professional engineer and have your insurance company sign off on the final design. Thanks.
 
Last edited:
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Back
Top