Finding a max load from the yield stress

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SUMMARY

The discussion focuses on calculating the maximum load a bar can withstand based on its yield stress and dimensions. The bar, measuring 500mm in length, 10mm in width, and 3mm in depth, has a maximum yield stress of 150 MPa. The user calculated the bending moment to be 3.75 at 250mm using a shear bending diagram but encountered confusion regarding the final load calculation. The bar is simply supported at both ends, which is crucial for determining the maximum load it can handle.

PREREQUISITES
  • Understanding of bending moment and shear force diagrams
  • Familiarity with yield stress concepts in materials science
  • Knowledge of the formula for stress: stress = moment / inertia
  • Basic principles of mechanics of materials
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  • Study the calculation of bending moments in simply supported beams
  • Learn about the relationship between yield stress and maximum load capacity
  • Explore the concept of moment of inertia and its role in beam bending
  • Review examples of load calculations for various beam configurations
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Engineering students, mechanical engineers, and anyone involved in structural analysis or materials testing will benefit from this discussion.

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1. Homework Statement I have a bar, 500mm long (0.05m) 10mm wide (0.01m) and 3mm deep (0.003 m)The bat has a load applied in the centre of 30nI know the maximum yield stress is 150 mpa 150x10^6How do I calculate the maximum load the bar can take?2. Homework Equations I used stress = m y / I3. The Attempt at a Solution I calculated the bending moment to be 3.75 at 250mm (.25m) using a shear bending diagram,*I then reversed the equation above to get:150x10^6 = 0.0015m/2.25x10^-11Which gives m as : (150x10^6 x 2.25x10^-11) / 0.0015M = 2.25I know the bending moment is at .25 mSo divide 2.25 / .25I get 9The answer can't be 9n as the question uses 30nCan someone please show me how to solve this?.Thanks in advance x*
 
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You missed the most important point. How is the bar supported?
 
Sorry, the bar is simply supported at either end
 

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