Calculating Charge Interactions: Half-Speed & Beyond

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AI Thread Summary
The discussion focuses on calculating the speed of a charge q when it moves infinitely far from a fixed charge Q and determining the distance at which q reaches half that speed. The user successfully calculated the speed at infinity to be approximately 9.07 m/s but struggles with finding the distance for half that speed. They initially attempted to use the kinetic energy equation but found their approach incorrect. Other participants are encouraged to provide insights or solutions to help resolve the user's confusion. The thread highlights the importance of understanding energy conservation in charge interactions.
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Homework Statement



A fixed charge Q= +3.65 µC is held fixed at the origin of an xy plane. A second charge q= +5.11 µC is released from rest at the xy coordinate of (+1.15 m, +0.810 m).

a) (a) If the mass of q is 2.90 g, what is its speed when it moves infinitely far from the origin?

(b) At what distance from the origin does q attain half the speed it will have at infinity*?
(*Please note where most of the energy exchange occurs!)

--------

Homework Equations



Ei=Ef
KQq/r=Fe=qV
1/2mv^2


The Attempt at a Solution



I solved for a) and got 9.07202 m/s
Can't seem to figure out way to do b. Initially I just took 1/2 the velocity I got in a), plugged it into the equation KQq/r=1/2mv^2 to solve for a n R, but that's wrong. Any help is appreciated.
 
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