Calculating Charge of Two Spheres in Equilibrium

AI Thread Summary
Two plastic spheres, each with a mass of 100.0 mg, are suspended and repel each other when charged, achieving equilibrium at 10 cm apart. The gravitational force on each sphere must be balanced by the electric force due to their charges. The calculation involves using the formula F=kq²/r², where the angle of displacement and the geometry of the setup are crucial for determining the charge. The attempt yielded a charge of approximately 2.5x10^-7 C, while the book states the answer is 8x10^-9 C. Analyzing the height difference due to displacement and the energy required is essential for accurate calculations.
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Homework Statement


Two plastic spheres each of mass 100.0 mg are suspended from very fine insulating strings of length 85 cm. When equal charges are placed on the spheres, the spheres repel and are in equilibrium when 10 cm apart.
(a) What is the charge on each sphere?


Homework Equations


F=kq2/r2


The Attempt at a Solution


I assumed that the strings were attached to the same place at the top. This eventually gave tan theta = kq2/mgr2.
I did sin-15/85 to get theta
I then plugged in all the values and got around 2.5x10-7
The book answer is 8x10-9.

Thanks for your time
 
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Show your substitution and calculation.
 
I am hesitant to mention this, because when I follow this method, I arrive at a different answer than the given book answer. That said, I would analyze it like so:

Each sphere is repelled by an electric force that is sufficient to balance the gravitational force when the sphere is deflected 5 cm.

Draw a diagram - the spheres are connected to the ceiling by 85 cm strings and are displaced a total of 10cm (5cm each from vertical). What is the height difference from their displaced position and their straight down position? How much energy does that require?
 
Take the projection of L on the vertical line.
Difference in height h = L - Lcosθ.
 
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