Calculating Cube Deceleration on a Moving Board

  • Thread starter Thread starter caseys
  • Start date Start date
  • Tags Tags
    Cube Deceleration
AI Thread Summary
A 0.5m cube on a decelerating board is analyzed for its movement across the board's surface. The board decelerates at -8.5 m/s² while the cube decelerates at -3 m/s², resulting in a relative acceleration of 5.5 m/s² for the cube. To determine the time it takes for the cube to move 1.5 meters, the problem can be simplified by treating the board as stationary. The calculations show that understanding the relative motion is key to solving the problem effectively. This approach allows for accurate time estimation for the cube's movement.
caseys
Messages
14
Reaction score
0
A 0.5m cube is sitting on top, and at the end, of a 1m wide by 3m long board. Both the cube and board are traveling at a constant velocity of 10 m/s. The board begins to decelerate at -8.5 m/s squared. The cube decelerates across the top of the board at -3 m/s squared. How much time will it take for the cube to move 1.5 meters across the top of the board.

I can figure the problem out if the board was not moving but am stuck in trying to figure out how the board decelerating faster will affect the deceleration of the cube.
 
Physics news on Phys.org
If the board is decelerating at -8.5 m/s2 and and the box is decelerating at -3 m/s2, then, relative to the board[\b], the box is accelerating at -3- (-8.5)= 5.5 m/s2. Now just do it as if the board were not moving.
 
Got it! Thanks...
Casey
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top