Calculating Distance Traveled by Sam on Jet-Powered Skis

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To calculate the distance Sam lands from the base of the cliff, start by confirming the initial conditions: he accelerates up a 50 m high slope with a thrust of 160 N. The calculated acceleration up the slope is 0.76 m/s², leading to a velocity of 20.9 m/s at the top. After reaching the peak, Sam's horizontal and vertical velocities are 23.2 m/s and 4.10 m/s, respectively. The next step involves analyzing his projectile motion to determine how far he travels horizontally before hitting the ground. Understanding the time of flight and applying the equations of motion will yield the final distance from the base of the cliff.
powderchick81
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I need help desperatley with this problem.

Sam (65 kg) takes off (from rest) up a 50 m high, 10° frictionless slope on his jet-powered skis. The skis have a thrust of 160 N. He keeps his skis tilted at 10° after becoming airborne. How far does Sam land from the base of the cliff?

I believe I'm almost there but I'm stuck towards the end. :frown:

Any help would be nice.
 
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I've gotten this far

acceleration up the slope = .76 m/s^2

length of slope = 288m

velocity at the top of the slope = 20.9 m/s

initial velocity on the x-axis = 23.2 m/s

intial velocity on the y-axis = 4.10 m/s

initial acceleration on the x-axis = 2.42 m/s^2

initial acceleration on the y-axis = -7.34 m/s^2

Now I have no clue what to do.
 
I get the impression that he starts from rest at the bottom of the slope and accelerates up it until he goes over the top - 50 meters up - then he flies through the air until he reaches the ground again - on the same level that he started out from?
 
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