Calculating electric charge from graph (capacitor)

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SUMMARY

The discussion focuses on calculating the electric charge on a capacitor by integrating voltage over time. The initial voltage is 10 V, with a capacitance of 2 x 10-6 F and a resistance of 1 x 106 Ω. The integration should be performed from 0 to the time when the capacitor is fully charged, resulting in an estimated charge of approximately 236 Vs. Clarification is needed regarding whether the capacitor is charging or discharging, as this affects the interpretation of the voltage-time relationship.

PREREQUISITES
  • Understanding of capacitor charging and discharging principles
  • Knowledge of integration techniques in calculus
  • Familiarity with electrical units: farads (F) and ohms (Ω)
  • Experience with graphing software for voltage-time analysis
NEXT STEPS
  • Study the relationship between voltage and time in capacitor circuits
  • Learn about the mathematical integration of functions in physics
  • Explore the concept of charge calculation using the formula Q = C × V
  • Investigate the use of graphing tools for analyzing electrical circuits
USEFUL FOR

This discussion is beneficial for electrical engineering students, physics enthusiasts, and anyone involved in analyzing capacitor behavior in circuits.

krisu334
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Homework Statement
When charging a capacitor we obtained a graph of voltage in terms of time. From the graph, find the amount of electronic charge on the capacitor.
Relevant Equations
Initial voltage: 10 V
Capacity: 2*10^(-6) Fahr.
Resistance: 1*10^6 Ohm
Apparently, we need to integrate the functions from 0 to the time when it is fully charged. However, I integrated in terms of t so the soultion (according to a graph programme) should be around 236 Vs but I don’t see how this could help me.
 
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Hello @krisu334 ,
:welcome: ##\ ##!​
What is the expected relationship between ##V## and ##t##?
 
krisu334 said:
Homework Statement: When charging a capacitor we obtained a graph of voltage in terms of time. From the graph, find the amount of electronic charge on the capacitor.
Relevant Equations: Initial voltage: 10 V
Capacity: 2*10^(-6) Fahr.
Resistance: 1*10^6 Ohm

Apparently, we need to integrate the functions from 0 to the time when it is fully charged. However, I integrated in terms of t so the soultion (according to a graph programme) should be around 236 Vs but I don’t see how this could help me.
Hi @krisu334. In addition to @BvU ’s question:

Presumably V is the voltage across the capacitor. Are you charging or discharging? You say “Initial voltage: 10 V” which implies you are discharging. But you also say “from 0 to the time when it is fully charged” which implies charging.

Minor points, for information:
The unit of capacitance (not “capacity”) is the ‘farad’ (lower case), symbol ‘F’.
The unit of resistance is the ‘ohm’ (lower case), symbol ‘Ω’.
 
Well, what is the status?
 

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