1. The problem statement, all variables and given/known data Two 1.00µC charged particles are located on the x axis. One is at x = 1.00 m, and the other is at x = -1.00 m. Determine the electric field on the y axis at y = 0.400 m 2. Relevant equations Electric Field = ke * q / r^2 3. The attempt at a solution I know the x-components cancel out, so we're only left with the y-component. E= 8.99*10^9 * (1*10^-6 C / (square root(1^2 + .400^2)) and then you have to take the y-component into account, so you multiply that by sin(.400/(square root(1^2 + .400^2))... and then multiply everything by 2 because there are two different charged particles. I'm getting an answer of 5625 N/C, but apparently the answer is 5760 N/C.