Calculating Electric Potential for a Non-Negligible Thickness Toroid

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SUMMARY

The discussion centers on calculating the electric potential for a toroid with a non-negligible thickness, specifically addressing the linear charge density formula ##\lambda = \frac {q}{2\pi R}##. Participants express confusion regarding this formula's applicability due to the toroid's width of ##2a##, suggesting that the linear charge density should be lower than indicated. The conversation also highlights the challenge of determining charge distribution in a metallic toroid when thickness is considered. Participants seek clarity on how to accurately compute electric potential under these conditions.

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  • Understanding of electric potential and charge density concepts
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  • Knowledge of electrostatics, particularly in metallic conductors
  • Basic proficiency in mathematical expressions involving integrals and charge distributions
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Homework Statement
Please see below
Relevant Equations
Please see below
For A.1 of this problem,
1675405830601.png

The solution is
1675399497646.png

However, I have a doubt about the linear charge density ##\lambda##.

I don't understand how ##\lambda = \frac {q}{2\pi R} ## since this is not a thin ring, but has a non-negligible width of ##2a##

I think that the toroid has a larger area than thin circle with a circumference ##2\pi R## so linear charge density should be less than that expression.

EDIT: How would we calculate the electric potential if the thickness was not neglected?

Many thanks !

Problem from:
https://www.ipho2021.lt/uplfiles/Th2.pdf
https://www.ipho2021.lt/uplfiles/Th2-Solution.pdf
 

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1675414550671.png
 
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BvU said:
Thank you for your reply @BvU!

However, how would we calculate the electric potential if the thickness was not neglected?

Many thanks!
 
Callumnc1 said:
Thank you for your reply @BvU!

However, how would we calculate the electric potential if the thickness was not neglected?

Many thanks!
Since it is metallic, your first challenge would be to figure out the charge distribution. Good luck with that.
 
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haruspex said:
Since it is metallic, your first challenge would be to figure out the charge distribution. Good luck with that.
Thank you for your reply @haruspex! Yeah that seems hard!
 

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