Calculating Energy Absorption of 2.0kg Bag of Ice

AI Thread Summary
To calculate the energy absorption of a 2.0 kg bag of ice used to cool a cooler for 5.5 hours, start by determining the initial and final states of the ice. The ice starts at -4ºC and ends as liquid water at 3ºC, requiring calculations for both the phase change and temperature change. The relevant formula is power equals energy divided by time. By calculating the total energy absorbed during the melting and heating process, one can find the power of energy absorption. This approach provides a clear method for solving the problem.
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A 2.0 kg bag of ice is used to keep a cooler of pop cold for 5.5 h. If the ice had an initial temperature of -4ºC and, after 5h, was liquid water with a temperature of 3ºC, find the power of energy absorption.

Any help would be great. I don't know where to start:confused:.
 
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Zeitgeist said:
A 2.0 kg bag of ice is used to keep a cooler of pop cold for 5.5 h. If the ice had an initial temperature of -4ºC and, after 5h, was liquid water with a temperature of 3ºC, find the power of energy absorption.

Any help would be great. I don't know where to start:confused:.
Write out your givens and your unknown(s). Do you know which formula(e) to use? Is there a chapter in your text you've read over and considered?
 
Power = energy / time
 
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