Calculating Field Direction and Magnitude for Levitating Copper Wire

AI Thread Summary
To calculate the field direction and magnitude for a horizontal copper wire levitating with a current of 50 A moving east, use the formula F = IL x B = mg. Here, F represents the magnetic force, I is the current, L is the length of the wire (1.0 m), B is the magnetic field strength, m is the mass of the wire, and g is the acceleration due to gravity (9.81 N/kg). The mass of the wire can be determined from its volume and density, considering its diameter of 0.10 cm. Understanding the principles behind the equation is crucial for proper application. This approach ensures accurate calculations for the levitating wire's magnetic field.
g.gnunu
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how do i find the field direction and magnitude of a horizontal copper wire with a current moving East. length is 1.0m, diameter is .10cm, current is 50 A. the wire is being levitated.
 
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Use F=ILXB=mg.
 
field direction and magntiude

could you polease expand on the formula. what numbers do i plug in for mg?
 
m - mass of the wire
g - 9.81N/Kg. The force which a 1Kg mass exerts due to gravity.
 
g.gnunu said:
could you polease expand on the formula. what numbers do i plug in for mg?
The important thing isn't knowing which numbers to plug in where, it's understanding the principles behind the equation and where the equation comes from. Do you understand where the equation comes from?
 
Last edited:
how do i set up the formula to get the answer?
 

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