Calculating Force Needed to Overcome Resistance in m=1.45X10^6 kg Building

AI Thread Summary
To calculate the force needed to overcome resistance for a building weighing 1.45X10^6 kg, the force of friction (Ff) must be determined, which is 2.00 percent of the building's weight. The applied force (Fa) is equal to the friction force (Ff) when acceleration is zero. There is confusion regarding how to find Ff, as the normal force (Fn) is considered zero due to no acceleration. It is suggested to incorporate the acceleration due to gravity to accurately calculate the frictional force. Understanding the complete context of the problem is essential for finding a solution.
Kiyana
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Homework Statement



m= 1.45X10^6 kg
w=1.00X10^2 MJ
a=0 m/s^2
to over come the force resistance that was 2.00 percent of the building's weight

Homework Equations



Fa=Ff (force applied=force friction)

The Attempt at a Solution



Fa= Fn-Ff

Im confused on how to find the force friction, the Fn is 0 due to the fact that the acceleration is 0, but i have no clue how to find the Ff.
 
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I think you should post the whole problem on #1. I'm not really sure what's happening here.
 
Kiyana said:

Homework Statement



m= 1.45X10^6 kg
w=1.00X10^2 MJ
a=0 m/s^2
to over come the force resistance that was 2.00 percent of the building's weight

Homework Equations



Fa=Ff (force applied=force friction)

The Attempt at a Solution



Fa= Fn-Ff

Im confused on how to find the force friction, the Fn is 0 due to the fact that the acceleration is 0, but i have no clue how to find the Ff.

I am hesitant to say that I cannot help you. You must post the "proper context" of the problem. Just giving off values will not assist you. I am also not sure what are you trying to find out. The force of friction ? If that is so then why don't you consider the acceleration due to gravity if force resistance is 2.00 percent of the building's weight.
 
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