Calculating Forces and Acceleration in Motion Problems

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To calculate the average force needed to accelerate a 7.00-gram pellet to 175 m/s over 0.700 m, the correct approach yields an average force of 875 N after converting mass to kilograms. For the fisherman problem, the forces acting on the fish must be analyzed, considering the upward tension and downward weight to determine the fish's mass. In the baseball scenario, the initial velocity is 45 m/s, and upon striking the mitt, the final velocity is 0 m/s, leading to an acceleration of -9205 m/s² and a calculated force of -1289 N. It is crucial to ensure unit consistency throughout the calculations. The discussions emphasize careful attention to units and the correct interpretation of motion problems.
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8. What average force is needed to accelerate a 7.00-gram pellet from rest to 175 m/s over a distance of 0.700 m along the barrel of a rifle?

9. A fisherman yanks a fish out of the water with an acceleration of 4.5 m/s^2 using very light fishing line that has a "test" value of 22 N. The fisherman unfortunately loses the fish as the line snaps. What can you say about the mass of the fish?

10. A 0.140-kg baseball traveling 45.0 m/s strikes the catcher's mitt, which, in bringing the ball to rest, recoils backward 11.0 cm. What was the average force applied by the ball on the glove?3

I tried doing number 8 on my own.

vfinal^2=vinitial^2 + 2ad
175m/s=0^2 + 2a(0.700m)
a= 125m/s
F=ma
F=(7.00g)(125 m/s)
F=875N

Is this correct>? How do you do the others?
 
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for number 8 - CAREFUL about the units. Mass is ALWAYS (make it a habit to convert it to) Kilograms.

for number 9 - Well if you are lifting a weight upward by a string, what are the forces that the weight would feel? ANd since this is upward motion you need only to care about those poiting upward and downward. Create a reference system in which upward is positive and downward is negative (the opposite is fine as well, as long as you are consistent with this reference system). Try to form something like this:
Sum of all the forces = Net Force
ANd test means tension here.

For number 10 - What is hte initial velocity, final velocity, distance it traveled before it came to a stop, thus can you find the acceleration? And find the force. Since it is a vector specify the direction, was the force in the original direction that the ball was going or the opposite?
 
It says the baseball recoils backward 11.0 cm. Is that the distance?
 
airelemental135 said:
It says the baseball recoils backward 11.0 cm. Is that the distance?

yes.. and again careful with the units
 
i used the formula vfinal^2=vinitial^2 + 2ad to calculate the velocity, and got 0. Is this correct? if so, the force would end up being 0?
 
i meant to calculate the acceleration
 
hgow did u get zero? What is the value of v1? and the value of distance?
 
v initial i put is 45 m/s, v final is 45 m/s distance is .11m
 
what should it be?
 
  • #10
airelemental135 said:
v initial i put is 45 m/s, v final is 45 m/s distance is .11m
Read the question. What happens to the ball when it is caught in the met?
 
  • #11
it bounces back .11 meters
 
  • #12
oh so vfinal should be 0? because it says its at rest when it hits the mitt
 
  • #13
Is this right now?

Vfinal ^2 = vinitial ^2 + 2ad
(0)^2=(45.0m/s)62 + 2a(.11m)
0m/s=2025m/s + .22a
a=-9205m/s^2
F=ma
F=(0.140kg)(-9205m/s^2)
F=-1289N

right?
 
  • #14
are you still there stunner5000pt ?
 
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