Calculating Forces on a Crate on a Frictionless Ramp

  • Thread starter 1stcool
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In summary, a crate with a mass of 210 kg is being pushed up a frictionless ramp at a constant speed by a horizontal force. The question is asking for the magnitude of the force exerted by the ramp on the crate. The normal force can be found by using the equation Fg*cos⊙(26), but this only applies if there is no horizontal force. To find the normal force, one must consider all the forces acting on the crate and apply the conditions for equilibrium. There are three forces in this scenario: Fg, F, and Fn. The correct approach is to consider all three forces and use the conditions for equilibrium.
  • #1
1stcool
4
0
please help me with this phy problem, thx

In Figure 5-39, a crate of mass m = 210 kg is pushed at constant speed up the frictionless ramp ( = 26.0°) by a horizontal force F.

http://www.webassign.net/hrw/hrw7_5-39.gif

What is the magnitude of the force exerted by the ramp on the crate?




I use m*g to find Fg, and then using Fg*cos⊙(26) to find Fn(normal Force) but I got it wrong, can anybody help me, thx.
 
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  • #2
The normal force would be [itex]mg cos\theta[/itex] only if there were no horizontal force F. Instead, consider all the forces acting on the crate (I see three) and apply the conditions for equilibrium.
 
  • #3
three? is it Fg, F and Fn?
 
  • #4
1stcool said:
three? is it Fg, F and Fn?
That's correct.
 
  • #5
Doc Al said:
That's correct.
ok, thanks Doc Al
 

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