Calculating Gamma Ray Count Rate Error in 20 secs

swaha
Messages
5
Reaction score
0

Homework Statement


A detector is used to count the number of gamma rays from a radioactive source if the number of counts is 10000 in exactly 20 secs then what is the error in counting rate per sec?



Homework Equations

- no idea.



The Attempt at a Solution

- As per our syllabus we had only done Geiger muller counter which gives a dead time & from that we can calculate the error. However that is not given here. SO I got no idea to approach. Please help.

Options given- 5%, 22.4%, 44.7%, 220% (absolute values all).
Question source TIFR GS 2010.
 
Physics news on Phys.org
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top