Calculating Gas Pressure in a Nebula with 100 Atoms/cm^3 and 7500 K Temperature

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The discussion revolves around calculating the gas pressure in a nebula with 100 atoms/cm^3 at a temperature of 7500 K. The initial calculation yielded a pressure of 1.02 * 10^-16 atm, which raised concerns about its validity due to its extremely low value. Participants noted that such low pressure is expected in interstellar space, confirming the calculation's accuracy. A comparison with the molar volume of an ideal gas at standard temperature and pressure (STP) further supported the result, indicating that the pressure is consistent with the conditions described. Overall, the calculations and reasoning presented align with the expected physical properties of the nebula.
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Homework Statement


A nebula-- a region of the galaxy where new stars are forming contains a very tenuous gas with 100 atoms/ cm^3. This gas is heated to 7500 K by the uv radiation from nearby stars. What's the gas pressure in atm?


Homework Equations





The Attempt at a Solution



100 atoms * 1mol/6.022*10^23 atoms = 1.02 * 10^-16 moles
1 cm^3 * (1m/100cm)^3 = 1 * 10^-6 m^3
R= 8.31 J/mol K
pV=nRT
p(10^-6 m^3) = (1.02 * 10^-16 mol)(8.31)(7500 K)
p= 1.03 * 10 ^-11 Pa = 1.02 * 10 -16 atm Does this seem too small to you?
 
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bcjochim07 said:
100 atoms * 1mol/6.022*10^23 atoms = 1.02 * 10^-16 moles

How did you divide 100 by Avogadro's number and get 10^-16?

p= 1.03 * 10 ^-11 Pa = 1.02 * 10 -16 atm Does this seem too small to you?

We are talking about interstellar space here. The pressure is going to be very low...

Here's a check you can do. The molar volume of an ideal gas at STP (about 300 K) is 22.4 liters, so there is roughly 0.05 mole/L or 5 x 10^-5 mole/cc . This is 25 times hotter, so that would lower the number of moles by a factor of 25, which would be 2 x 10^-6 mole/cc ; that's still at 1 atmosphere. How many atoms are in the one c.c. at this point?

If you reduce the number of atoms to 100, what does the pressure become? That will give you the order of magnitude (and maybe one sig-fig) of the pressure.

EDIT: That suggests that your answer is OK, but you mistyped your number of moles...
 
Last edited:
oops it should be the 1.66 * 10 ^ -22, that was the answer I typed in as moles. I came up with the answer correctly though. Other than that it looks fine?
 
The check I describe confirms your result. So it seems to be just fine...
 
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