Calculating Impulse in a Collision: Positive or Negative Velocity?

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To calculate impulse during a collision, the change in velocity (Δv) is critical, defined as Vfinal - Vinitial. The direction of velocity is arbitrary; if the initial velocity is positive, the final velocity after rebounding should be negative. The correct impulse calculation is based on the chosen sign convention, leading to two potential outcomes: 0.63 kg.m/s or 2.73 kg.m/s, depending on how the final velocity is defined. It's essential to maintain consistency in the sign convention throughout the calculation. Understanding that the change in velocity reflects the direction of motion is key to resolving any confusion.
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Homework Statement



a tinnes ball of mass 150 gm moves with velocity 11.2 m/s to collide with a racket , after collision it is rebounded with vilocity 7 m/s ...find :-the impulse of the racket on the ball.

Homework Equations



I = m (delta) v


what i want to know .. is
when do we use the vilocity with the negative direction ??

i mean when we answer it

can we calculate

0.15 * ( 11.2-7)= 0.63 kg.m/s

or

0.15* (11.2-(-7))=2.73 kg.m/s

so what is the right answer ?!
 
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Think about it. If we define the direction of the initial velocity to be positive, than what must the sign of the resultant final velocity be?

Hint: The ball's final velocity is opposite in direction to it's initial velocity.
 
i know

i thought that second answer is the right one as it is opposit in direction

but i found different answers in the books so i got confused

but also i want to understant ... we want to find the change in velocity so when we give the final one -ve sign we will add them so how ?

im sorry I am asking a lot of questios

thank u
 
The change in velocity is always Vfinal - Vinitial.

The direction that you call negative is arbitrary. For example, if you call toward the racket as positive, then away from the racket must be negative.

Pick a sign convention, then determine Vfinal and Vinitial.
 
thank u
 
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