Calculating Incline Distance for Rotational Motion

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SUMMARY

The discussion centers on calculating the distance a hollow cylinder (hoop) rolls up an incline of 15 degrees when initially moving at a velocity of 3.3 m/s. The correct approach involves equating both translational and rotational kinetic energy to gravitational potential energy. The user initially calculated a distance of 0.56 meters, but the accurate answer, as per the textbook, is 4.3 meters. This discrepancy highlights the necessity of considering both forms of kinetic energy in the calculations.

PREREQUISITES
  • Understanding of rotational motion principles
  • Knowledge of kinetic and potential energy equations
  • Familiarity with energy conservation in physics
  • Basic trigonometry for incline calculations
NEXT STEPS
  • Study the conservation of energy in rotational motion
  • Learn about the moment of inertia for hollow cylinders
  • Explore the equations for translational and rotational kinetic energy
  • Investigate the effects of incline angles on motion dynamics
USEFUL FOR

Students and educators in physics, particularly those focusing on mechanics and rotational motion, as well as anyone seeking to understand energy conservation in dynamic systems.

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A hollow cylinder(hoop) is rolling on a horizontal surface at v = 3.3 m/s when it reaches an incline of 15 degrees. how far up the incline will it go?

this was in the chapter about rotational motion but from my understanding of it, it can be solved just by taking the kinetic energy and having it equal the potential energy. when i did that the answer i got was 0.56 meters but the answer in the book is 4.3, I am guessing that what i did doesn't work. Anyone care to explain?
 
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Did you take into account both rotational and translational kinetic energy?
 

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