Calculating induced power in coil

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SUMMARY

This discussion focuses on calculating the induced power in a coil subjected to a changing magnetic field. The user is constructing a coil using a 3/8" x 2.25" bolt and plans to expose it to a 2000 gauss field from a 0.5" x 0.5" neodymium magnet. The induced voltage can be calculated using the formula V = -n (dφ/dt), where n represents the number of turns in the coil and φ is the magnetic flux. The discussion highlights the importance of source impedance in determining the overall power output of the coil.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the formula for induced voltage (V = -n (dφ/dt))
  • Knowledge of coil construction and wire specifications (e.g., 20 gauge magnet wire)
  • Basic concepts of source impedance in electromechanical systems
NEXT STEPS
  • Research the calculation of source impedance in moving magnet coil arrangements
  • Explore the effects of back electromotive force (back emf) on induced power
  • Learn about the relationship between magnetic field strength and induced voltage
  • Investigate transformer transfer functions and their application to coil systems
USEFUL FOR

Electronics engineers, physicists, and hobbyists interested in electromagnetic induction, coil design, and power generation from magnetic fields.

Jdo300
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Hi,

I'm working on making a coil and I was wondering if there are some nifty equations out there to predict how much power the coils can make under a changing magnetic field of X gauss. I am going to be using 1 inch of a 3/8" x 2.25" bolt to wind my coil onto and I will be exposing it to a 2000 gauss field from a 0.5" x 0.5" neo magnet that is placed on the end of the coil.

I used a gauss meter to measure the amount of flux coming out of the side of the bolt where I will be wrapping the wire, and it is about 320 gauss. If I could mechanically vary this field strength on the coil by ±5% (304 - 336 gauss) at frequency X, how would I determine the power output? I am planning on using 20 gauge magnet wire for the coil, which will be 1" tall, and 1.5" in diameter.

Any help/pointers would be great :smile:
 
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Induced *power* is an interesting question. The power that can be induced will depend on the source impedance of the electromechanical setup, and I'm not sure how one would go about calculating that. Interesting question. Calculating the induced voltage is fairly straightforward,

V = -n \frac{d\phi}{dt}

where n is the number of turns in the coil, and \phi is the total flux that crosses the area of the coil.

But the weaker the source of the flux, the more the back emf will cancel it out -- the situation is much like a the transfer function through a transformer. But I'm not sure how to calc source impedance of a moving magnet coil arrangement. Anybody else know?
 

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