Calculating Internal Energy Absorbed in Truck Cab After Collision

AI Thread Summary
The discussion focuses on calculating the internal energy absorbed by components of a truck cab during a frontal impact test as per ECE R29 regulations. The user seeks assistance in determining energy absorption after a swing bob, weighing 1500 kg and impacting with 40 KJ of energy, strikes the cab. While acknowledging the complexity of crash testing and the potential for computer simulations, the user emphasizes the need for hand calculations to complement their simulation work. The conversation highlights the challenges of analyzing multi-component systems in crash scenarios. Ultimately, the user is looking for guidance on performing these calculations effectively.

Is this Question is Worth posting??

  • yes

    Votes: 0 0.0%
  • no

    Votes: 0 0.0%

  • Total voters
    0
prasadpatrudu
Messages
4
Reaction score
0
How to calculate Energy absobed by the components of a Truck Cab after crash test??

Hi,

I have a question regarding the calculation of internal energy of components after collision.
In conducting the frontal impact test as per the ECE R29 regulation, a swing bob has to hit the front of the cab fixed to chassis with some force, and after that we have to calculate the energy absorbed by the components of the components of the cab. can anyone please help me out in solving this problem?? details of the above problem as follows..

weight of the swing bob = 1500 kg
dimension of the swing bob = length 2500 mm, height 800 mm, centre of gravity of swing bob should coincide with lateral axis of the CAB.
Distance from geometric centre of bob to the point of suspension = 3500 mm
impact energy given to the bob = 40 KJ
coefficient of static friction = 0.2
coefficient of dynamic friction = 0.2
as of my knowledge
Total energy = Kinetic Energy + Internal Energy(absorption energy)
as the friction energy is very small we can neglect that.
Total weight of the truck cab = 1 ton
Thank you...
 
Last edited:
Engineering news on Phys.org


Doubt you'd get anything meaningful from this.

Crash testing, or any multi-component system deforming is a pain to analyze.
 


Hi Chrish,

It is crash test for a Truck Cab, which is composed of multiple components, frankly speaking I'm dealing with crash simulation projects in an MNC, can tou help in this regard??
 


prasadpatrudu said:
Hi Chrish,

It is crash test for a Truck Cab, which is composed of multiple components, frankly speaking I'm dealing with crash simulation projects in an MNC, can tou help in this regard??

So is it just a computer simulation you are doing or a full simulation including practical tests?
I thought you meant a hand calculation when I answered before.

If you are using a computer to simulate then there are others on this forum with far more knowledge than me. They will be able to help you better than I could.
 


Yes, I'm doing a computer simulation, but I need hand calculations as you thought.
Please help out in this regard.
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Back
Top