Calculating Ion Charge (given Electron Configuration)

AI Thread Summary
Calculating the ionic charge of transition metals like iron from their electron configuration is complex due to the filling order of sub-orbitals, specifically the 4s and 3d orbitals. Iron's neutral configuration is 1s22s22p63s23p64s23d6, and it commonly exhibits ionic charges of 2+ and 3+, which can be attributed to various quantum mechanical effects. The stability of different oxidation states is not straightforward and often appears random, influenced by factors such as electron-electron interactions and energy levels. Understanding which electrons are involved in ionization requires knowledge of the energy levels and can involve transitions between orbitals. For further clarity, researching the Aufbau principle may provide insights into the order of orbital filling.
FeDeX_LaTeX
Science Advisor
Messages
436
Reaction score
13
Hello;

My physics teacher told me that there was a way to calculate the ionic charge of a transition metal given its electronic configuration, but he did not tell me how, because it is 'too complicated'. I can't find any useful webpages on the subject, either... my teacher said that the subject was "too A-level" and that I don't need to know...

I will use an example. We can figure out that iron has an electronic configuration of 1s22s22p63s23p63d8. However, it has an ionic charge of 2+ (and sometimes 3+... why can it be either?). My question is, given this piece of information, how can one calculate iron's ionic charge? Or do you need more information?

Thanks.
 
Physics news on Phys.org
FeDeX_LaTeX said:
I will use an example. We can figure out that iron has an electronic configuration of 1s22s22p63s23p63d8. However, it has an ionic charge of 2+ (and sometimes 3+... why can it be either?). My question is, given this piece of information, how can one calculate iron's ionic charge? Or do you need more information?

Well, actually (neutral) iron should be:
1s22s22p63s23p64s23d6 (or in short [Ar]4s23d6).
See, 4s fills up before 3d.

I think what you're asking is 'How do you know which oxidation states are stable'?
Well the short answer is: Experience.
A bit more would be to say that it's very difficult because there are very many different effects involved here, mostly coming from quantum-mechanics (and in some cases, special relativity as well). If there was some kind of simple rule for it, we'd be teaching it. Of course, some rules you learn, such as noble gas configurations being are stable, mostly hold true.

So it basically appears to be very random. Manganese will happily form a Mn(V), but Iron will practically never lose 5 electrons, even though it has one more than Manganese!
 
Last edited:
Hello;

Thanks! Okay, so the sub-orbitals are filled in a set order? Okay, I understand. Is there a pattern? I think I remember seeing an illustration depicting the order of the different sub-orbitals.

So it appears to be random? Okay... so what determines if, say, whether or not Fe(II) or Fe(III) will be formed? I will try to research some of these 'different effects' you describe, there must be some good e-books around.

Also... if ionization occurs, on, say, a neutral iron atom, how do we know which electron is affected? If an electron absorbs a photon and is raised to a higher energy level, does that mean that, for example, an electron may move from 4s to 3d?

Cheers
 
FeDeX_LaTeX said:
so the sub-orbitals are filled in a set order? Okay, I understand. Is there a pattern?

Google aufbau principle.
 
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top