Calculating Kp for a Gas-Phase Equilibrium Reaction

In summary, the equilibrium pressure of Xe in a reaction mixture initially containing 2.24 atm Xe and 4.27 atm F2 is 0.34 atm. Using the equation Kp=(PXe)(PF2), the equilibrium constant for the reaction can be calculated to be 25. The reaction in question is Xe(g) + 2F2(g) ---> XeF4(g), and the remaining Xe has gone to the formation of XeF4. The partial pressures at equilibrium can be determined using the given equation and the expression for Kp.
  • #1
rcrx
16
0
A reaction mixture initially contains 2.24 atm Xe and 4.27 atm F2. If the equilibrium pressure of Xe is 0.34 atm, determine Kp for the reaction.

This question came out of the blue, and all I can think of is that Kp=(PXe)(PF2), but the answer is supposed to be 25.

I don't get it? Any suggestions? Thanks!
 
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  • #2
Initial pressure of Xe was 2.24 atm, at equilibrium it was 0.34 atm. What have happened to the rest of Xe?

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methods
 
  • #3
It must have left the container? I don't know, really :\
 
  • #4
Question asks about reaction equilibrium constant... What reaction?

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  • #5
Oh, sorry. Xe(g) + 2F2(g) ---> XeF4(g)
 
  • #6
So again, what happened to the rest of the Xe?
 
  • #7
The rest of Xe has gone to the formation of XeF4
 
  • #8
Can you now figure out the partial pressures of all species at equilibrium?

And take another look at the expression you have for Kp (compare with the equation in post#5).
 

Related to Calculating Kp for a Gas-Phase Equilibrium Reaction

1. What is equilibrium pressure?

Equilibrium pressure is the pressure at which a chemical reaction reaches a state of balance, where the rates of the forward and reverse reactions are equal.

2. How is equilibrium pressure related to Kp?

Kp, or the equilibrium constant in terms of partial pressures, is a measure of the extent to which a reaction proceeds towards equilibrium at a given pressure. It is directly related to the equilibrium pressure, as Kp increases with increasing equilibrium pressure.

3. How is Kp calculated?

Kp can be calculated using the equilibrium expression, which is the ratio of the partial pressures of the products to the partial pressures of the reactants, each raised to the power of their respective coefficients in the balanced chemical equation.

4. How does temperature affect Kp?

The value of Kp is temperature-dependent, as it is affected by the enthalpy and entropy changes of the reaction. Generally, Kp increases with increasing temperature for endothermic reactions, and decreases with increasing temperature for exothermic reactions.

5. How can Kp be used to predict the direction of a reaction?

If the value of Kp is greater than 1, the reaction favors the formation of products at equilibrium. If the value of Kp is less than 1, the reaction favors the formation of reactants at equilibrium. If the value of Kp is equal to 1, the reaction is at equilibrium.

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