Calculating Magnetic Flux Density for Zeeman Splitting 0.05 /cm

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To calculate the magnetic flux density needed for a Zeeman splitting of 0.05 /cm in hydrogen's ground state, the relationship between energy and magnetic field must be understood. The energy difference (delta E) can be expressed as delta E = Ub B, where Ub is the Bohr magneton. It is essential to recognize that "magnetic flux density" refers to the magnetic field B. Converting the wavenumber of 0.05 /cm into frequency and subsequently into energy is a critical step in determining the required magnetic flux density. Understanding these concepts will enable the calculation of the necessary magnetic field for the specified Zeeman splitting.
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Homework Statement



What magnetic flux density is required to produce a zeeman splitting of 0.05 /cm in the ground state of hydrogen?


Homework Equations





The Attempt at a Solution



I\'ve worked out that delta E in the ground state is Ub B where Ub is the Bohr magneton. But how do i work out the flux density requied to produce that splitting?!
 
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Not sure exactly where your confusion lies, but I'm guessing it's one of two areas:

1. Are you aware that "magnetic flux density" is the same as the magnetic field B?

2. Can you convert the 0.05/cm wavenumber value into a frequency, and from there into an energy?
 
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