Calculating Mechanical Energy on a Water Slide

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SUMMARY

The discussion centers on calculating the mechanical energy of a child sliding down a water slide, specifically a 50.8 kg child with an initial velocity of 0.9 m/sec. The mechanical energy (ME) at the top of the slide is derived from kinetic energy (KE), calculated as ME=0.5 * mass * velocity^2, resulting in ME=20.58 Joules. The potential energy (PE) is considered zero at the water level, and the conservation of mechanical energy principle is emphasized, stating that ME remains constant unless non-conservative forces like friction are present.

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A 50.8 kg child slides down a water slide with a velocity of 0.9 m/sec at the top. At the bottom of the slide, she is moving horizontally, y=2.5 meters above the water. She splashes into the water d=3 meters to the left of the bottom of the slide.

a) Assuming potential energy to be zero at the water level, what is the mechanical energy of the child at the top of the slide?

For this, ME=PE+KE. Since PE=0, ME=0+KE. So ME=0.5 (50.8) (0.9^2), but that's not right.

b) How high is the top of the slide above the bottom of the slide?
I don't know how to do this one.
 
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Mechanical energy is a conserved quantity. Unless things like friction are involved (non conservative forces) but the problem would state this outright.

Therefore the mechanical energy at the bottom of the slide is the same as the top.

You are using the KE at the top of the slide plus the PE at the bottom of the slide.. that is not right, you need to add the KE and PE at the same place to find the ME.
 

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