Calculating Negative Electric Charge of Oxygen Gas at STP

AI Thread Summary
To calculate the negative electric charge of all electrons in a 56-liter sample of diatomic oxygen gas (O2) at STP, one must first determine the number of O2 molecules in that volume. This involves using the ideal gas law or a related formula to find the number of molecules present. Each O2 molecule contains a specific number of electrons, which can be multiplied by the total number of molecules to find the total charge. The discussion emphasizes the importance of independently researching the necessary formulas rather than relying on others for direct answers. Understanding the foundational concepts is crucial for solving the problem effectively.
dtrain121
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Homework Statement


Find the negative electric charge of all the electrons in a 56 liter sample of oxygen gas at STP. Assume the oxygen gas is diatomic.


Homework Equations





The Attempt at a Solution


I have no idea. Please help
 
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Hello,

Diatomic, of course, means that each oxygen molecule contains 2 oxygen atoms (ie, O2). Cool. So you know you have 56 liters of a gas, oxygen here, at STP. Do you have a formula that would allow you to calculate how many molecules of O2 gas would occupy that much volume? After you calculate that, its a simple matter of finding out how many electrons each O2 molecule contains, and multiplying your number of molecules by the number of electrons in each molecule by the total charge of each electron.

Hope this helps, reply if you need more clarification! I've deliberately avoided simply giving you the formulas, of course.
 
he did not give me any formulas. i would not know where to start. can you please give me the formulas?
 
dtrain121 said:
he did not give me any formulas. i would not know where to start. can you please give me the formulas?

You need to start by calculating the number of atoms of the gas that are contained in a 56 liter container, at STP-- ie, 1 atmosphere, and 0 degrees C.

No, I will not give you the formula. You should be able to find this one on your own. It's one of the more famous formulas out there. Have you even looked for it? Or thought about where you could?

We're not here to do your work for you.
 
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