Can you work out the acceleration of the object?NickS606 said:I'm sorry I am still new, can I get a better explanation please?
Do you know any Kinematic (SUVAT) equations?NickS606 said:How can I do that?
Really? Then I'm going to go ahead and say take a look in your textbook or class notes and find them.NickS606 said:I'm just going to go ahead and say I have never even heard of those equations.
Perhaps, but we'll have to do some work first.NickS606 said:Ya I don't really recall those. Anyways, would I do [tex]a_{ave} = \Delta v / \Delta t[/tex]
No. Did you just pluck those numbers out of thin air?NickS606 said:I did 12N/3.5s and my answer is 3.4, is this correct?
Okay. Have you looked for the kinematic equations in your notes or text?NickS606 said:I got the numbers out of the question, and there is no diagram, it is height and width for sure though.
Okay, well we cannot use that equation. Try reading http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/1DKin/U1L6a.html" and see if it jogs your memory.NickS606 said:Well there aren't many notes and all I could find was this equation [tex]v_{ave} = \Delta x / \Delta t[/tex]
The highlighted coefficient should be 0.5 rather than 1.5, but yes, this is the equation to use. Can you start filling in the known variables?NickS606 said:I'm just not getting it, I assume the equation to be used is
d=vi*t+1.5*a*t^2
One may use the above formula even if the initial velocity is non-zero.Delphi51 said:Yes, that formula will do it if the initial velocity is zero.
Acceleration is what you want to find out! You need to solve for the acceleration.NickS606 said:Is it d=0*.50s+.5*a*.50s^2
I put a for acceleration because I don't know what acceleration is :/
The formula for calculating net force on a 2kg mass down an 8m incline is: Fnet = mgsin(theta), where Fnet is the net force, m is the mass, g is the acceleration due to gravity (9.8 m/s^2), and theta is the angle of the incline.
The unit for net force is Newtons (N).
The angle of the incline can be calculated using the formula: tan(theta) = opposite/adjacent, where theta is the angle, opposite is the height of the incline, and adjacent is the length of the incline.
Calculating net force on a mass down an incline helps determine the acceleration of the mass. This can be used to understand the motion of objects on an incline and to make predictions about their behavior.
Yes, the net force can be zero if the mass is at rest or if the forces acting on the mass are balanced. This typically occurs when the incline is at a certain angle, known as the equilibrium angle, where the forces pulling the mass down the incline and the forces pushing the mass up the incline are equal.