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klmgirly
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A box of mass 5.0-kg is accelerated from rest across a floor at a rate of 2.0m/s^2 for 7.0s. Find the net work done on the box?
W=Fd
W=Fd
Calculating net work done on an accelerating box.
- Thread starter klmgirly
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- Accelerating Box Net Work Work done
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SUMMARY
The net work done on a 5.0-kg box accelerated from rest across a floor at a rate of 2.0 m/s² for 7.0 seconds is calculated using the formula W = Fd. The force (F) can be determined using Newton's second law, F = ma, where 'm' is the mass and 'a' is the acceleration. The distance (d) traveled by the box can be calculated using the equation d = 0.5 * a * t², resulting in a total work done of 70 joules.
PREREQUISITES- Understanding of Newton's second law (F = ma)
- Knowledge of kinematic equations for uniformly accelerated motion
- Familiarity with the work-energy principle
- Basic proficiency in unit conversions (e.g., kg to Newtons)
- Study kinematic equations for calculating distance in uniformly accelerated motion
- Learn about the work-energy theorem and its applications
- Explore examples of calculating net work done in various physical scenarios
- Review concepts of force and mass in different contexts, such as friction and incline planes
Physics students, educators, and anyone interested in understanding the principles of mechanics and work calculations in physics.
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