Calculating Peak-to-Peak Amplitude of Out-of-Phase Sine Waves

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Two sine waves with equal peak-to-peak amplitudes of 81 and a phase difference of 90 degrees will result in a resultant wave with a peak-to-peak amplitude of 81. The discussion highlights the importance of graphing the functions to visualize the intersections, which indicate the maximum and minimum amplitudes of the resultant wave. The mathematical representation of the waves is provided, suggesting the use of sine functions to analyze their behavior. Understanding the phase relationship is crucial for determining the resultant amplitude. Overall, the peak-to-peak amplitude remains unchanged despite the phase difference.
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Two sine waves have equal peak to peak amplitudes 81 but are out of phase by 90 degrees. What is the peak to peak amplitude of the resultant wave.


I have no idea how to start this question, could someone give me guidance?
 
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Graph
40.5sin(\omega t-\frac{\pi}{2}) and 40.5sin(\omega t)
The points on the graph where these functions intersect are where the resultant will have its maximum (and minimum) amplitudes.
 
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