Calculating Pendulum Speed: 20cm Length, 10 Degree Angle at Top - Solution

  • Thread starter Thread starter zee
  • Start date Start date
AI Thread Summary
To calculate the speed of a pendulum with a length of 20 cm and a 10-degree angle at the top of its swing, use the principle of conservation of energy. At the bottom of the swing, all potential energy converts to kinetic energy, meaning the total energy is equal to kinetic energy (E = K). The height at the top can be determined using the angle, which helps calculate the potential energy. By establishing the origin at the bottom of the swing, potential energy is zero there, simplifying the calculations. The final speed at the bottom of the swing is 0.24 m/s.
zee
Messages
1
Reaction score
0
I have no idea how to do this problem. What equation do I use?

The pendulum on my clock is 20 cm long. At the top of the swing, it makes an angle of 10 degrees with the verticle. What is the speed of the pendulum at the bottom of the swing?

The answer is 0.24 m/s, but how?

Thank you.
 
Physics news on Phys.org
Use consevation of energy. The intial angle will give you the information you need to find the height for the potential energy.
 
Conservation of energy can be a tricky thing to learn to use at first, so here's a couple of hints.

Conservation of energy tells us that K (kinetic energy) + U (potential energy) = E (total energy).

Put the origin of the coordinate system where the pendulum is at the bottom of its arc. Why do we do this? Well, what can you say about the system when the pendulum is at the origin? Its height is zero, so the potential energy (due to gravity) is also zero.

Since E = K + U, always (when energy is conserved), at this point you know E = K + 0 = K. All energy of the pendulum is kinetic.

Using this line of thinking, when is E = U?

Once you figure that out, and start writing the equaions, the problem will practically solve itself.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top