Calculating Power Generated by DC Generator for 6V Battery

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To calculate the power generated by a DC generator for charging a 6V battery, the voltage can be determined using the equation E = N B v sin(theta). However, to find the actual power output, the resistance of the load (light bulb) must be known, as power is calculated using P = V^2/R. The generator's impedance also needs to be considered to accurately assess the power delivered to the battery. Understanding these variables will help in determining how effectively the battery can be charged to power the light bulb for the desired duration. Proper calculations will ensure the project meets its energy requirements.
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Hi, I'm trying to work on this interesting little project that involves charging a 6V battery using a simple DC generator powered by a wheel spun manually. The equations for the DC generator output would be :


E = N B v sin(theta) x 10-8

if I'm correct. E being the voltage, N=number of turns, B=flux density, and theta is the angle between the coil's vector and the magnetic field.

My problem is, this only gives me the voltage. How would I get the actual power generated by the generator? All I know about the battery is that it is 6V and 5AH.

My goal is to have the battery power up a light bulb for a given duration. Any ideas?
 
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P = V^2/R

If the generator gives the impedance you can plug the numbers.
 
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