Calculating Pressure Difference in Two Tanks

AI Thread Summary
To calculate the pressure difference between two tanks containing SAE Grade 30 oil and carbon tetrachloride, the densities of the fluids are essential. The pressure in tank A is calculated using the formula P = Po + pgh, resulting in PA = 890 kg/m³ * 1.1 m * 9.8 m/s². For tank B, PB is calculated as 1590 kg/m³ * 0.8 m * 9.8 m/s². The resulting pressure difference PB - PA is found to be 2871.4 Pa. The discussion also raises a question about the use of Torr for calculating pressure difference, indicating a need for clarity on unit conversions in fluid mechanics.
etothey
Messages
22
Reaction score
0

Homework Statement


Two tanks, one containing SAE Grade 30 oil (density of 890 kg/m3) and the other containing carbon tetrachloride (density of 1,590 kg/m3) , are connected through a differential manometer as shown in the figure. Calculate the pressure difference between chambers A and B.
Pressure_5.jpg: http://www.imageupload.org/thumb/thumb_8614.jpg



Homework Equations


760mm Hg = 760Torr. 760Torr = 1atm = 101300Pa.
P= Po + pgh


The Attempt at a Solution


The pressures are the same if there would have been no height difference.
Thus PA=890*1.1*9.8
and PB=1590*0.8*9.8
PB-Pa=2871.4 Pa.
This correct?
Quick question. why can't I use 0.3*300Torr to solve for pressure difference?
new to fluids.
 
Physics news on Phys.org
anyone?
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

What is the absolute pressure in a tank measured by a manometer?
Replies
1
Views
2K
Finding the gauge pressure at the bottom of a barrel
Replies
4
Views
3K
Calculate the pressure difference between two points
Replies
10
Views
9K
How to Calculate Pressure at the Bottom of an Oil Drum?
Replies
2
Views
2K
Pressure difference in two pipelines
Replies
1
Views
8K
Pressure Question using 'mm-Hg'
Replies
1
Views
7K
Pressure difference when height changes
Replies
1
Views
5K
Pressure and depth in a static fluid
Replies
1
Views
9K
Bernoulli? Difference in water pressure between floors
Replies
6
Views
10K
Pressure difference between two bulbs measured by a mercury manometer
Replies
1
Views
4K

Hot Threads

Recent Insights

Back
Top