Calculating Pressure for a Hydraulic Car Lift

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To calculate the pressure required to raise a car using a hydraulic lift, the area of the larger piston must be determined using the formula Area = π(diameter²)/4. The pressure on the smaller piston is equal to the pressure on the larger piston, which can be calculated using the formula Pressure = Force/Area, where Force is the weight of the car (mass multiplied by gravity). The discussion highlights the importance of understanding that the larger piston supports the car's weight while the smaller piston requires the calculated pressure to lift it. There is some confusion about whether the problem requires the force needed or just the pressure. Accurate calculations are essential for effective hydraulic lift operation.
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A car service station uses a hydraulic car lift, the diameter of its pistons are 0.02 m and 0.32 m calculate the pressure required to raise a car of mass 1800 KG
I don't know how to get the area ?
 
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Key words: piston, diameter
 
Area = pi times diameter square over 4?? And I'm going to put the diameter of the larger pistol eh?
 
The larger diameter piston supports the weight of the car. The problem is asking you how much pressure must be applied to the smaller piston (assuming the smaller and larger pistons are connected hydraulically) to support the weight of the car.
 
The pressure on the small piston is equal to the pressure of the large piston so I'm going to calculate the pressure of the large piston by the rule F/A force =mg where g is the force of gravity and area = pi diameter square over 4 ?
 
Douna2nd said:
The pressure on the small piston is equal to the pressure of the large piston so I'm going to calculate the pressure of the large piston by the rule F/A force =mg where g is the force of gravity and area = pi diameter square over 4 ?
Sure, but I note that you don't need to know the smaller diameter for that. I would have expected the question to ask for the force needed. Maybe it asks for that later?
 
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