Calculating Pull Force on Weights Connected by Cords

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SUMMARY

The discussion focuses on calculating the pull force (P) required to accelerate a series of weights connected by cords, specifically a vertical strand of four balls with masses of 5 kg, 10 kg, 15 kg, and 20 kg, under an upward acceleration of 4.00 m/s². The correct approach involves using the equation F = ma, where the total mass (m) is the sum of the individual weights. The participant initially calculated the pull force as 552 N, which was incorrect due to an error in summing the masses. The correct pull force is determined to be 690 N after proper calculations.

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Motorboar
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Homework Statement


A series of weights connected by very light cords are given an upward acceleration of 4.00 m/s2 by a pull P, as shown in Fig. 5.3.( a vertical strand of 4 balls with mass 5,10,15,and 20 kg with the pull at the top) A, B, and C are the tensions in the connecting cords.
the pull P is closest to:

290 N
690 N
50 N
200 N
490 N

Homework Equations


F= ma


The Attempt at a Solution


treating the weights as one mass
Pull-mg=ma
pull=m(a+g)
= 552
Which is not one of the answers. What is the error in my logic?
 
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Motorboar said:

The Attempt at a Solution


treating the weights as one mass
Pull-mg=ma
pull=m(a+g)
= 552
Which is not one of the answers. What is the error in my logic?

I'm don't see an error in your logic (if I'm interpreting your description of the figure correctly). :approve: Maybe there's an error in your calculations? :rolleyes: What did you use for m and g?

[Edit: In other words, your equations seem fine. But I don't know why you ended up with 552]
 
added the masses wrong xD Thank you.
 

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