Calculating Q such that E(0,0,0)=0

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Homework Statement
Attached below.
Relevant Equations
Attached below.
Question

1636907568790.png

Relevant equation;
gif.gif

My attempt:
%5C%5C%20Solve%5C%3Bfor%5C%3BQ%20%5C%5C%5C%5CQ%3D2.gif


Could someone please confirm my answer?
 
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Electric field at the Origin contributed from half ring is of direction - y and its magnitude is expressed by integral
[tex]\frac{1}{4 \pi \epsilon_0} \int_0^\pi \frac{\rho r \sin\theta d\theta }{r^2}[/tex]
where r is radius of half ring, ##\rho## is line density of its charge.
 
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The component radial is cancel out, because of all direction of component radial around circle center
 

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